Mars Leather Gold Iridium Lenses

[andr3]

The Gold Iridium lens on the Mars Leather looks brighter and more translucent than other Gold Iridium lenses to me. Anybody else feel that way?
(Is it actually Leather Gold Leather Gold Iridium ? Not sure if the statement about the orange base is accurate on O-Review, though )

 

[CarGuy]

I see no differences.

 

[Oakininam]

I see no differences.

Same

 

[Funky-Trixtar]

I noticed there was a definite tonal difference, between the Gold Iridium, used on my Leather Mars, and the ones for later generation M Frames.
I'll try and find my observations on here.

Anybody know if Oakley changed the appearance of Gold Iridium?

A question which I'm not entirely sure of the answer. I bought a pair of Gold Iridium lenses to replace my scratched Leather Mars pair. The only thing is, the seller (trixie26te) states they're cut from genuine O lenses and she has 100% positive feedback and the pics do show good lenses...

www.oakleyforum.com

 

[andr3]

I noticed there was a definite tonal difference, between the Gold Iridium, used on my Leather Mars, and the ones for later generation M Frames.
I'll try and find my observations on here.

Anybody know if Oakley changed the appearance of Gold Iridium?

A question which I'm not entirely sure of the answer. I bought a pair of Gold Iridium lenses to replace my scratched Leather Mars pair. The only thing is, the seller (trixie26te) states they're cut from genuine O lenses and she has 100% positive feedback and the pics do show good lenses...

www.oakleyforum.com

Thanks for linking that thread. Post Anybody know if Oakley changed the appearance of Gold Iridium? pretty much sums it up:
A) there are variations in Gold (or any, for that matter) Iridium.
B) Even in his picture the Mars lens looks different from all others. It does look like my lens, too.

 

[CarGuy]

After further review and after wearing mine in full sun yesterday I'm inclined to agree that the Mars are more translucent and seem a little more subdued than my other 24K metals.